Solution:
We are given:
μ=73,σ=8,n=8
We have to find P(Mean >75)
To find this probability, we need to find the z score:
z=(xbar-μ)/(σ/sqrt(n))
=(75-73)/(8/sqrt(23))
=1.20
Now we have to find P(z>1.20)
Using the standard normal table, we have:
P(z>1.20)=0.1151
Therefore the probability that the average score of the 23 students falls above 75 is 0.1151