Heat required =5.81 J
mass of gold= 3 grams
change in temperature = ΔT=36-21=21°C
specific heat of gold=0.129 j/g C
now heat= Q= m C ΔT
Q=3 (0.129)(15)
Q=5.81 J
Thus the heat required= 5.81 J
6.2m questions
8.2m answers