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The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 78 inches, and a standard deviation of 16 inches. what is the probability that the mean annual precipitation during 64 randomly picked years will be less than 80.8 inches?

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The sample mean is μ=78, and sample standard deviation is σₓ=σ/
√(n)=16/
√(64)=2.

The Z-score is
Z=(80.8-78)/(2) =1.4.

The required probability


P(X<80.8)=P(Z<1.4)

Refer to standard normal distribution table.


P(Z<1.4)=0.9192

User Oleksandr Shtykhno
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