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3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l) If you could drop 12 atoms of copper into a beaker containing nitric acid, how many molecules of NO would be produced? : 12 2 8 4
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3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l) If you could drop 12 atoms of copper into a beaker containing nitric acid, how many molecules of NO would be produced? : 12 2 8 4

User Mannu
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8 molecules of NO....
User Douglasrcjames
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