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User JMarsch
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(q)/(q^2+5q+6)+(1)/(q^2+3q+2)=(q)/(q^2+3q+2q+6)+(1)/(q^2+q+2q+2)\\\\=(q)/(q(q+3)+2(q+3))+(1)/(q(q+1)+2(q+1))\\\\=(q)/((q+3)(q+2))+(1)/((q+1)(q+2))\\\\=(q(q+1))/((q+1)(q+2)(q+3))+(1(q+3))/((q+1)(q+2)(q+3))\\\\=(q^2+q+q+3)/((q+1)(q+2)(q+3))=(q^2+2q+3)/((q+1)(q+2)(q+3))\to B.

User Shibbir
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