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3 votes
Write the sum using summation notation, assuming the suggested pattern continues.

2-6+18-54+...

1 Answer

6 votes

Each term seems like it's -3 times the previous one, first term 2.


\displaystyle \sum_(k=0)^(\infty) 2 (-3)^k

Going to infinity like that it's of course divergent, but perfectly summable if we replace infinity with a finite bound like n-1:


\displaystyle \sum_(k=0)^(n-1) 2 (-3)^k

But, assuming the pattern continues means I'd go with infinity.

Answer:
\displaystyle \sum_(k=0)^(\infty) 2 (-3)^k

User Lucas Huang
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