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43 votes
43 votes
Solve the equation

3x/3x-1 + 2/x = 1

User McGo
by
2.7k points

2 Answers

14 votes
14 votes

Answer:

x= 2/7

Explanation:

Multiply both sides by the common denominator

3x^2 +6x−2=3x^2 −x

Move everything to the left side.

3x^2+6x-2-3x^2+x=0

Simply.

7x-2=0

Separate the cosntants and variables.

7x=0+2

Add or subtract zero

7x=2

Then divide both sides by 7.

7x/7=2/7

Cancel out common factors in the numerator and denominator

x=2/7

User Gremo
by
3.0k points
26 votes
26 votes

Answer:

x = 2/7

Explanation:

You want to solve the equation 3x/(3x-1) + 2/x = 1.

Solution

It works nicely to subtract 1 from both sides, then simplify.


(3x)/(3x-1)+(2)/(x)=1\\\\(3x)/(3x-1)\cdot(x)/(x)+(2)/(x)\cdot(3x-1)/(3x-1)-(x(3x-1))/(x(3x-1))=0\\\\(3x^2+6x-2-3x^2+x)/(x(3x-1))=0\qquad\text{combine terms}\\\\(7x-2)/(x(3x-1))=0\qquad\text{simplify}\\\\7x-2=0\qquad\text{expression is 0 when numerator is 0}\\\\\boxed{x=(2)/(7)}\qquad\text{add 2, divide by 7}

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Additional comment

The values x=0 and x=1/3 would make the denominator zero, so are excluded from the domain of the equation. By working the problem this way, we ensure that extraneous solutions do not present themselves.

User Joshua Obritsch
by
3.1k points