Question

Here is another one thank you again to everyone helping me out

Answer 1

To solve this questions, we can remove the common factors that are present both in the numerator and denominator. We can start with the numbers. Looking at 6 and 15, they have a GCF that is not 1, meaning that we can remove something from them. Their GCF is 3, so we can remove the common factor of 3. We can remove this by dividing each of them by the GCF. 6/3 is 2, and 15/3 is 5.

Now, we can cancel out the common factor of the variables. We see that the variable 'g' is in both the denominator and numerator. That means we can cancel it out using the same method as before. This gives us our final fraction of:

`(2g^(2)h^(3))/(5)`

Answer 2

Simplify. Note that there is a 6 in the numerator, and 15 in the denominator.

Divide 3 from both numbers

6/3 = 2

15/3 = 5

Next, divide g from both numerator and denominator.

g³/g = g²

g/g = 1

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You're simplified equation will be:

(2g²h³)/5

hope this helps