Question

I don’t know how to start with drawing the diagram for this question.

Answer 1

Consider right triangles ADB and ADC in the figure, right angle D.

By alternate transversals ABD=63° and ACD=11°.

`\tan 63 = \frac 8 y`

`\tan 11 = \frac 8{x+y}`

`y = (8)/(\tan 63)`

`x = -y + (8)/(\tan 11)`

`x = (8)/(\tan 11) - (8)/(\tan 63)`

`x \approx 37.08 \textrm{ meters}`

That's in one second, so

Answer: 37 meters per second