I’m very lost, someone please help!!!

asked May 24, 2019 130k views

4 votes

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$\cot\theta-\sqrt3=0\ \ \ \ |+\sqrt3\\\\\cot\theta=\sqrt3\to\ \theta=(\pi)/(6)+k\pi,\ k\in\mathbb{Z}\\\\Answer:\ \theta=(\pi)/(6),\ (7\pi)/(6)$

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