Question

Maybe someone can help me out with this or give me the equation to find mols/liters - thanks to if you can help, here's the question given to me.

Complete the following chart using data you completed in chart above for question 3. (Remember that a bowl of soup is made by adding 150 mL of water to the 250 mL can of condensed soup).


The chart asks for the Concentration (mol/L)

in one can of soup Concentration (mol/L)
in one bowl of soup

-Both of them are asking for table salt and table sugar

Answer 1

Answer :The correct answers are :

Concentration in one can soup : Table salt = 6.12
`(mol)/(L)`

Table sugar = 5.84
`(mol)/(L)`

Concentration in one bowl Soup : Table salt = 3.82
`(mol)/(L)`

Table sugar = 3.65
`(mol)/(L)`

Concentration : It is quantity to measure a solution . It can be defined as abundance of constituents per volume of solution . The most used concentration is molar concentration .

Molar concentration is defined as mole of solute present in volume of solution . The unit of concentration is
`(mol)/(L)` . It is expressed as :

`Concentration ( (mol)/(L) ) = (mole of solute (mol))/(Volume of solution (L))`

Concentration in one can of soup (Volume = 250 mL )

Volume of one can soup = 250 mL . Converting it from mL to L as :

(1 L = 1000mL)

`Volume of one can soup = (250 mL)/(1000mL) * 1 L = 0.250 L`

A) Concentration of table salt :

Following are the steps to find out molar concentration :

Step 1 : Find mass of solute :

Since mass of solute is not given , so we take solubility of NaCL in 1 L of water . Solubility is maximum amount of NaCL that can be dissolved in 1 L water at room temperature . From image , we can say that 359 g of NaCL can be dissolved ideally in 1 L of water .

Since volume of solution is 0.250 L , so mass of salt in 0.250 L can be found :

Mass of NaCL in 1 L = 359 g

Mass of NaCL in 0.250 L of water = 359 g * 0.250 L

Mass of NaCL in 0.250 L = 89.75 g

Step 2 : Convert mass of solute to its mole

Mole can be calculate from mass as :

`Mole (mol) = (given mass (g) )/(molar mass (g)/(mol))`

Molar mass of Table salt (given ) = 58.44
`(g)/(mol)`

plugging value of mass and molar mass in mole formula :

`Mole = (89.75 g )/(58.44 (g)/(mol))`

Mole of Table salt = 1.53 mol

Step 3 : To find concentration .

Mole of solute = 1.53 mol

Volume of solution ( one can of soup ) = 0.250 L

Plugging these values in Concentration formula :

`Concentration = (1.53 mol)/(0.250 L)`

Concentration of Table salt in one can soup = 6.12
`(mol)/(L)`

B) Concentration of Table sugar :

Following steps can be used :

Step 1: To find mass of Table sugar

Since mass of sugar is not given , so solubility of sugar will be considered . From image solubility is 2000 g in 1 L of water .

Since volume of one cup soup is 0.250 L , so mass of Sugar in 0.250 L of solution =

Mass of sugar in 1 L of water = 2000 g

Mass of sugar in 0.250 L of solution = 2000 g* 0.250 L

Hence , mass of Sugar in 0.250 L of solution = 500 g

Step 2 : To convert mass of sugar to its mole

Mass can be converted to mole using same formula. Plugging value in mole formula :

`Mole of sugar = (500 g)/(342.3 (g)/(mol))`

Mole of sugar = 1.46 mol

Step 3 : To find concentration of Sugar :

Mole of sugar = 1.46 mol

Volume of solution = 0.250 L

Plugging these values in concentration formula :

`Concentration = (1.46 mol)/(0.250 L) = <strong>5.84</strong> (mol)/(L)`

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Concentration in one bowl of soup :

Volume of one bowl of soup = 150 mL water + 250 mL of one can soup

= 400 mL

Converting mL to L : ( 1 L = 1000mL )

`Volume of solution = (400 mL)/(1000mL) * 1 L`

Volume of solution = 0.400 L

A) Concentration of Table salt :

Similar steps will be used :

Step 1: T find mass of Table salt

Again solubility will be used , which is =359 g in 1 L .Since 150 mL water is added which had no salt . hence all the salt was present in 250 mL one can soup , so mass of salt present in one can soup will be used .

Mass of Table salt = 89.75 g

Step 2: To convert mass to mole

Mass can be converted using mole formula .

Mole of Table salt = 1.53 mol ( calculated above )

Step 3: To find concentration

Mole of Table salt = 1.53 mol

Volume of one bowl soup = 0.400 L

Plugging these values in Concentration formula as:

`Concentration = (1.53 mol)/(0.400 L )`

Concentration of Table salt in one bowl soup = 3.82
`(mol)/(L)`

B) Concentration of Table sugar :

Step 1 : To find mass of Table sugar

Mass of sugar in 0.400 L will be same as that of mass of sugar present in 0.250 L since water had no sugar .

Mass of Table sugar = 500 g

Step 2 : To convert mass to mole

Mole can be calculated using mole formula ( as calculated above for one can soup )

Mole of Table sugar = 1.46 mol

Step 3: To find concentration

Mole of Table sugar (solute ) = 1.46 mol

Volume of one bowl soup = 0.400 L

Plugging these values in concentration formula :

`Concentration = (1.46 mol)/(0.400 L)`

Concentration of Table sugar in one bowl soup = 3.65
`(mol)/(L)`

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Also Note :You have marked Table sugar as Ionic which is incorrect .Table sugar is covalent as it has all non metals .