*This is on the assumption that the equation is
![(2y)^{(3)/(2)}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/f0q8ydqm9pq4gleq9al3al0jwcozv2hmxj.png)
So firstly, you'll need to rewrite this as
![2^(3)/(2)*y^(3)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lo4u5bevdwsakebcilrosbh6v5zibzla9m.png)
Next, remember the rule for exponents to radicals: "
. Applying this rule to both would look like this:
![√(2^3)*√(y^3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/k982ojhc529pivhl6xoftlu3axb7ofiwcr.png)
Next, simplify 2^3:
![√(8)*√(y^3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8qlb9dfh5zej5bw5rzsnrz3iz7siiqu5xr.png)
Next, apply the product rule of radicals (√ab = √a*√b) to this expression, and your answer will be
![√(8y^3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/xg2w4zg2dhamtn4omgqv564i0gyd69wqh4.png)