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Solve x^3=27?

A. x = 3
B. x = 3 and x = –3
C. x = 9
D. x = 9 and x = –9

plz help asap
plz

User Antirez
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1 Answer

3 votes
Your answer is A. x = 3.

This is because to solve x³ = 27, we need to cube root both sides of the equation, and the cube root of 27 is 3.

It cannot be -3, as -3 × -3 × -3 = 9 × -3 = -27.

I hope this helps!
User Headmaster
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