Question

The area of a rectangle is 55 ft squared

, and the length of the rectangle is 4 ft
less than three times the width. Find the dimensions of the rectangle.

{Algebra 1 }

Answer 1

So you would have to set up an equation to solve for x. Your equation would be w(3w-4)=55 w=the width that would simply to 3w^2-4w=55 then you move the 55 over so its 3w^2-4w-55=0 you can solve that on a calculator by graphing and finding the zeros but in this case the positive zero is your answer.

so w=5

the width is 5

the length is 11

hope this helps!

Answer 2

W = width

Length is 4 ft less than three times the width L = 3W - 4

A = L x W

55 = (3W - 4)(W)

55 = 3W^2 - 4W

3W^2 - 4W - 55 = 0

(3W + 11)(W - 5) = 0

Width can't be negative so

W - 5 = 0; W = 5

L = 3W - 4 = 3(5) - 4 = 11

Answer:

Length = 11 ft

Width = 5 ft