Question

Can you help me ? correct me if I'm wrong, thank you !

Answer 1

`\sf Hello!`

•
`\sf h = -2`
•
`\sf k = -3`
•
`\sf x = -1`
•
`\sf y = -5`


`\sf Then,`


`\sf Coefficient \: of\: squared\: expression.\: in\: parabola's\: Eqn.` :


`\sf y` =
`\sf a(x - h)^(2)` +
`\sf k`

⇒
`\sf a = (\sf y - k)/(\sf (x - h)^(2))`

⇒
`\sf a = (\sf -5 + 3)/(\sf (-1 + 2)^(2))`

⇒
`\sf a = (\sf -2)/(\sf 1)`

⇒
`\boxed{\sf a = \sf -2}`


`\sf Hence,`

`\sf Coefficient \: of\: squared\: expression.\: is\:D.\: -2`

~
`\sf iCarl`

Answer 2

y=a(x-h)^2+k (vertex form)

where h=-2, and k=-3 (vertex)

so

substituting (-1,-5)

y=a(x+2)-3

solve for a

a=(y+3)/(x+2)

substituting (-1,-5)

=(-5+3)/(-1+2)

=-2/1

=-2

Yes, your answer is correct. Well done.