Question

A point charge (q1) has a magnitude of 3.0 x10-6 C. A second charge (q2) has a magnitude of -1.5 x10-6 C and is located 0.12 m from the first charge. Determine the electrostatic force each charge exerts on the other.

Answer 1

Answer:2.81 N

Step-by-step explanation:

Given

`q_1=3* 10^(-6)\ C\\q_2=-1.5* 10^(-6)\ C`

distance between them r=0.12 m

Electrostatic force is
`F=(kq_1q_2)/(r^2)`

Putting values

`F=(9* 10^9* (3* 10^(-6))* (-1.5* 10^(-6)))/(0.12^2)\\F=2.81\ N`