Let X be the number of traffic accidents that occur on a particular stretch of road during a month. X follows a Poisson distribution with a mean of μ =7.3
The probability function of X is given by
P(X=x) =

We have mean =7.3
P(X=x) =

Probability of observing exactly four accidents on this stretch of road next month is
P(X=4) =

= (0.0006755 * 2839.8241)/24
P(X=4) = 1.9184113/ 24
P(X=4) = 0.0799338
P(X=4) = 0.079934
Probability that there will be exactly four accidents on this stretch of road next month is 0.079934