Question

What is the density in g/L of gas with a molar mass of 2.016 g/mol at 4.77 atm and 118k?

Answer 1

n / V = P / RT = (4.77 atm) / ((0.08205746 L atm/K mol) x (118 K)) = 0.4926 mol/L

(2.016 g/mol) x (0.4926 mol/L) = 0.993 g/L

Answer 2

0.9926 g/L is the density of gas.

Step-by-step explanation:

Molar mass of gas = M = 2.016 g/mol

Mass of gas = m

Density of the gas = d =
`(Mass)/(Volume)=(m)/(V)`...(1)

Pressure of the gas = 4.77 atm

Temperature of the gas = T = 118 K

`PV=nRT=(m)/(M)RT`

`P=(m)/(V* M)RT`

`(P* M)/(RT)=d`..(From (1))

`d=(4.77 atm* 2.016 g/mol)/(0.0821 atm l/mol K* 118 K)`

d = 0.9926 g/L

0.9926 g/L is the density of gas.