95.1k views
3 votes
Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. what percentage of light was actually absorbed by the sample?

1 Answer

2 votes

Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. This means that the remainder of the light was absorbed by the sample given in the question.

Now, from the 100% light that has been incident on the sample, if 85% was transmitted, then the percentage of light was actually absorbed by the sample can be found out as:

percentage of light was actually absorbed by the sample=100% - (percentage of light transmitted by the sample)

Therefore, percentage of light was actually absorbed by the sample=100%-85%=15%

Thus, 15% light was actually absorbed by the sample.

User Zoey Mertes
by
5.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.