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In triangle ABC, a = 9, c = 5, and B = 120°. Find b^2

1 Answer

6 votes

We can find b by using the cosine rule of a triangle.


b^2=a^2+c^2-2ac CosB

First step is to plug in the given values in the above equation. So,


b^2=9^2+5^2-2*9*5*Cos (120)


b^2=81+25-90(-(1)/(2) )

=106+45

=151

So, b^2=151

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