to the risk of sounding redundant.
well, in a triangle, the midsegment is half of its parallel base, namely in this case BD = ½AE.
well, what is the length of BD anyway?
well, we know its coordinates are -1,3 and 2.5,3
AC = 2 BD
Distance BD = √[(2.5+1)^2 +(3-3)^2]
Distance BD = √(3.5)^2
Distance BD = 3.5
AC = 2 * 3.5 = 7
Answer
d. 7
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