Question

48a2 + 32a2 + 16a by 4a?

Answer 1

In a similar way to how we distribute multiplication across addition (ex: 2 x (3 + 2) = 2 x 3 + 2 x 2) we can distribute this division, too. We divide each term individually by 4a, and then add them back together again:

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Adding all those divided terms together, we get the expression 12a² + 8a + 4, which is D.

Answer 2

(48a^3 + 32a^2 + 16a) / 4a = ?

48a^3 / 4a = 12a^2

32a^2 / 4a = 8a

16a / 4a = 4

so

(48a^3 + 32a^2 + 16a) / 4a = 12a^2 + 8a + 4

Answer is D. 12a^2 + 8a + 4