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An arithmetic sequence has the terms a6=53 a 6 = 53 and a8=61 a 8 = 61 . Questions: What is the value of d d ? AnswerIncorrect What is the value

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The given terms are two terms apart, so their difference is twice the difference of adjacent terms.


a_8-a_6=2d=61-53=8\\\\d=(8)/(2)=4

The value of d is 4.

User Owaiz Yusufi
by
7.8k points
4 votes

Answer:

The value of d is 4.

Explanation:

It is given that the 6th term of an AP is
a_6=53 and 8th term is
a_8=61.

The nth term of an AP is


a_n=a+(n-1)d

6th term of an AP is
a_6=53.


a_6=a+(6-1)d


53=a+5d .... (1)

8th term is
a_8=61.


a_8=a+(8-1)d


61=a+7d .... (2)

Subtract equation (1) from equation (2).


61-53=a+7d-(a+5d)


61-53=a+7d-a-5d


8=2d

Divide both sides by 2.


4=d

Therefore the value of d is 4.

User Big Bad Baerni
by
7.9k points
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