Question

A 22.0 kg child is riding a playground merry-go- round that is rotating at 40.0 rev/min. What centripetal force must

Answer 1

F = 482.51 N

Step-by-step explanation:

Given that,

Mass of a child, m = 22 kg

Angular velocity of the merry-go-round,
`\omega=40\ rev/min`

Let the radius of the path, r = 1.25 m

We need to find the centripetal force acting on the child. The formula for the centripetal force is given by :

`F=m\omega^2r\\\\=22* (4.18879)^2* 1.25\\\\=482.51\ N`

So, the required centripetal force is 482.51 N.