We're given two points and two half lines, aka rays.
Point slope form says the line through (a,b) with slope m is
![y-b = m(x-a)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kl9ygv9qvbc7lmde6nw55btclhlfakr2bo.png)
We can write that in slope-intercept form:
![y = mx + (b-ma)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jx46haaksxdqakccgc1ef7j6ogmph06lfx.png)
The left line goes two up for every one to the right, that's a slope of 2. It ends at (-1,-3). So that line is:
![y = 2x + (-3 -2(-1)) = 2x-1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/19hxa62qxok6439ged1iesuvvx1l7i2ytb.png)
We turn that into the ray we like with the condition
so it ends at our point.
The right ray has slope 1 and endpoint (1,5). That's
with the line
![y= x + (5-1(1))= x+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/l8em67nowkio1n0oills0oh5jnt0khtrof.png)
Answer: