Question

Solution suppose that a blood vessel of cross-sectional area a carries microbubbles at a speed v into a capillary bed. if the capillary bed is made up of n capillaries, each with cross-sectional area a, with what speed will the blood flow in the capillary bed

Answer 1

let u=speed of flow

A x v = n x a x u then u = A x v/ n x a

Answer 2

The speed of blood flow in the capillary bed is
`(1)/(n)` times the speed of blood flow in the blood vessel

Step-by-step explanation:

Let the cross-sectional area of blood vessel be "A"

The speed of flow of blood into the capillaries is "v"

Now , it is given that capillary bed is made up of w "n" numbers of blood vessels with cross section area "A" and and speed "V"

Now as per continuity equation of flow, the flow remains constant when the density is unchanged

Thus ,

Flow in single blood vessel is equal to flow in "n" capillaries of capillary bed

Therefore,

`Av= n*A*V\\v= nV\\or \\V= (v)/(n)`

Hence, the speed of blood flow in the capillary bed is
`(1)/(n)` times the speed of blood flow in the blood vessel