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Which point is on the circle described by (x - 2)^2 + (y + 3)^2 = 4?

(0, 0)

(2, 0)

(2, -5)

(1, -4)

1 Answer

2 votes

The point that would appear on the circle is (2, -5).

We can find this by using the values in the equation given. So, let's start with the equation.

(x - 2)^2 + (y + 3)^2 = 4

Now we add in our values for x and y.

(2 - 2)^2 + (-5 + 3)^2 = 4

And now we can solve and look for a true statement. If the statement is true at the end, we know it was on the line.

(2 - 2)^2 + (-5 + 3)^2 = 4

(0)^2 + (-2)^2 = 4

0 + 4 = 4

4 = 4 (TRUE)

User Hexaquark
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