In the question, it says that the picture is of a quarter circle. To represent the area, we use:

We have the area of the entire quarter circle now. Let's figure out the area of the triangle, and subtract it from the area of the quarter circle. It says that the radius is 1. Notice that the two legs of the triangle (not the hypotenuse, but the legs) are equal to the radius of the circle. Therefore, the base and the height of the triangle, since it's a right triangle, are both equal to 1. Let's plug that into the area of the triangle equation:

So, the area of the triangle is one half. Let's subtract it from the quarter circle, and we get:

Hope I helped!