Question

Ask the user to type in an integer greater than 50 and assign it to a variable called x. Write a program to calculate the sum of squares of positive integers. The loop should stop when the sum is greater than x. At the end of the loop print how many numbers were used to calculate the sum. For example, if x is 100, sum will be 91, and six numbers (1 to 6) were used to calculate sum.

Answer 1

The question involves writing a computer program that sums the squares of positive integers until the sum exceeds a user-entered value x. The user is prompted to enter an integer greater than 50, and the program will output the number of integers used to reach or exceed this sum.

Step-by-step explanation:

Writing a Program to Sum Squares of Integers Until Exceeding a Limit

The exercise involves writing a program where the user is prompted to enter an integer greater than 50, which is then assigned to a variable named x. The goal of the program is to calculate the sum of squares of positive integers until the sum exceeds the value stored in x. To achieve this, we use a loop that will run until the accumulated sum is greater than the variable x. Within the loop, we continually add the square of each successive integer, starting from 1. When the loop ends, the program should output the number of integers used in the sum. For instance, if x is 100, the sum of squares would reach 91 with six numbers, because 1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2 = 91, which is just under 100. The output would thus indicate that six numbers were used.

This programming problem combines simple arithmetic with control structures like loops and conditional statements, which are fundamental concepts in computer science and programming.

Answer 2

The solution in Python is as follows:

num = int(input("Number: "))

if num>50:

sum = 0

count = 0

for i in range(1,num):

count = count + 1

sum = sum + i**2

if sum > num:

sum = sum - i**2

count = count - 1

break;

print("Sum: "+str(sum))

print("Numbers: "+str(count))

else:

print("Number must be greater than 50")

Step-by-step explanation:

The condition stated in the question do not conform with the example. The question says, the loop should stop when sum > x.

But:

When x = 100 and sum = 91, the program loop should not stop because 91 is not greater than 100.

However, I'll answer based on the example given in the question.

This prompts user for number

num = int(input("Number: "))

The following if condition is executed if number is greater than 50

if num>50:

This initializes sum to 0

sum = 0

This initializes count to 0

count = 0

The iterates through the inputted number (e.g. 100)

for i in range(1,num):

This increases the count

count = count + 1

This calculates the sum of square of the positive integer

sum = sum + i**2

The following removes excess number from the sum

if sum > num:

sum = sum - i**2

count = count - 1

break;

This prints the calculated sum

print("Sum: "+str(sum))

This prints the count of number used

print("Numbers: "+str(count))

The following is executed if user input is less than 50

else:

print("Number must be greater than 50")