So firstly, you want to get rid of the outermost powers. The rule with powering something with an exponent is to multiply the exponents together.
In this case:
and
![(4y^3)^2=(4^(1*2)y^(3*2))=(16y^6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2s0dhmjrvs0k70doepl71fir6ue967a4ej.png)
Our current equation look like this:
![((-4x^2)(8x^(-6)y^3))/((16x^5)(16y^6))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/5x7v6cwbn669a4bk11tefg26iymgiwqtr1.png)
Next, you want to multiply what's on the numerators and the denominator. The rule with multiplying exponents of the same base is to add them together.
In this case:
![((-4x^2)(8x^(-6)y^3))/((16x^5)(16y^6))=(-32x^(2+(-6))y^3)/(256x^5y^6) =(-32x^(-4)y^3)/(256x^5y^6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/abmifgtbsruh16c91y0ziwtf27xapiyitw.png)
Now we can divide. The rule with dividing exponents with the same base is that you subtract them.
In this case:
![(-32x^(-4)y^3)/(256x^5y^6)=-(1)/(8) x^(-4-5)y^(3-6)=-(1)/(8) x^(-9)y^(-3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/z7krywi5xv222wf5lvd7wbfhnlaf09x9ux.png)
Now, if you're required to leave no negative exponents, the rule is that for example x^-2 would turn into 1/x^2. In this case, it would turn like this:
. And that would be your final answer.