Question

11.) Evaluate the integral

Answer 1

Hey there !

Check the attachment.
Hope it helps you :)

Answer 2

You can start with the indefinite integral

... ∫e^(ax)·dx = (1/a)e^(ax) +c

Then your definite integral is

`\int\limits_(-3)^(10){e^(-0.025x)}\,dx=(-1)/(.025)\left(e^(-0.025\cdot 10)-e^(-0.025\cdot(-3))\right)\\\\=40\left(e^(.075)-e^(-0.25)\right)\\\\ \approx11.9633`