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Hi! Can someone PLEASE help me out with this problem? I would like it if the person answering could explain it to me.

THANK YOU!

Hi! Can someone PLEASE help me out with this problem? I would like it if the person-example-1
User Rjmoggach
by
5.2k points

2 Answers

3 votes

(4x^2y^3z^5)^3

------------------- Your going to multiply everything by 3

(2x^5y^2z^6)^3



12x^6y^9z^15

--------------------

6x^15y^6z^18 Then you'll cancel things out. And remember you cant cancel exponents and variables that aren't the same.


So 12/6=2 x^15-x^6=x^9 y^9-y^6=y^3 z^18-z^15^3

If you cancel all the numbers to the top you get negative so I did it that you come out all positive.


2y^3

----------

x^9z^3


If you want it all at the top it'll be 2x^-9y^3z^-3



User Darren Corbett
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5.3k points
3 votes


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User Norkuy
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