Question

a car slows down -27.7 m/s to -10.9 m/s "while" undergoing a displacement of -105 m what was its acceleration

Answer 1

Acceleration of car=3.09 m/s²

Step-by-step explanation:

initial velocity= Vi=-27.7 m/s

Final velocity=-10.9 m/s

displacement=-105 m

using kinematic equation Vf²= Vi² + 2 a d

(-10.9)²=(-27.7)² + 2 a (-105)

-648.5=-210a

a=648.5/210

a=3.09 m/s²