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How can I create a sine graph that has a period of 2π and an amplitude of 3?

User Rosnk
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Hello!


The parent function of the graph of sin is y = sin(x).


Amplitude is the maximum displacement on the graph of a function.

Period is the displacement of x at which the graph of a function begins to repeat.

The period can be found by using the formula:
P = (2\pi)/(B).


Since the amplitude is 3, the graph of sin is y = 3sin(x).


Given the period 2π, we can substitute this value into the given formula,
P = (2\pi)/(B), to find B.


2π = 2π / B (multiply B to both sides)

2π · B = 2π (divide by 2π)

B = 1


Thus, the equation is y = 3sin(x). I'll post the graph as well.

How can I create a sine graph that has a period of 2π and an amplitude of 3?-example-1
User Hammad Hassan
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