Question

An automobile has a mass of 1500 kg. What is the minimum uncertainty in the velocity (in miles per hour) when its center of mass is located with an uncertainty no greater than 1 cm

Answer 1

`\triangle v=1.57*10^-^3^5miles/hour`

Step-by-step explanation:

From the question we are told that

Mass of of automobile M= 1500 kg

Generally the equation of the uncertainty principle is given by

`\triangle p=(h)/( \triangle x)`

`\triangle p=(1.054*10^-^3^4)/( 10^-^2)`

`\triangle p=1.054*10^-^3^2`

Generally the uncertainty in velocity is mathematically given by

`\triangle v=(\traingle p)/(m)`

`\triangle v=(1.054*10^-^3^2)/(1500)`

`\triangle v=7*10^-^3^6m/s`

Therefore the minimum uncertainty in the velocity (in miles per hour)

`\triangle v=7*10^-^3^6*(3600)/(1609.3)`

`\triangle v=1.57*10^-^3^5miles/hour`