1. Solve the triangle. A = 33°, a = 20, b = 13 (1 point)



The supplement of B (which has the same sine) is around 159° so with A exceeds 180 degrees so we ignore it.


Fourth choice: B = 20.7°, C = 126.3°, c ≈ 29.6
2. State whether the given measurements determine zero, one, or two triangles. C = 30°, a = 32, c = 16 (1 point)

That's unique, A=90°
One triangle.
3. Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 59°, a = 13, b = 14 (1 point)

There are two triangle angles with this sine, supplementary to each other,

Since when combined with A=59° neither A+B exceeds 180°, we have two valid triangles.




That's the last choice, suitably edited:
B = 67.4°, C = 53.6°, c = 12.2; B = 112.6°, C = 8.4°, c = 2.2