Question

Triangle ABC is translated 2 units down and 1 unit left. Then it is rotated 90 degrees clockwise about the origin to create triangle A'B'C'. What are the coordinates of the vertices of triangle A'B'C' ? A.) A'(-2, 0), B'(1, -1), C'(-1, -1) B.)A'(2, 1), B'(5, 0), C'(3, 0) C.) A'(-1, -2), B'(2, -3), C'(0, -3) D.) A'(-2, 1), B'(1, 0), C'(-1, 0)

Answer 1

its a

because i did the question

Answer 2

Answer : D.) A'(-2, 1), B'(1, 0), C'(-1, 0)

As per the given diagram

Point A : (0,0)

Point B: (1,3)

Point C : (1,1)

WE translate each point 2 units down and 1 unit left.

The points are in ordered pair (x,y)

For 2 units down we subtract 2 from y

For 1 unit left we subtract 1 from x

After translation

Point A : (0,0) ---> (0-1 , 0-2) ---> (-1, -2)

Point B: (1,3) ---> (1-1 , 3-2) ---> (0, 1)

Point C : (1,1) ---> (1-1 , 1-2) ---> (0, -1)

Now we rotated 90 degrees clockwise about the origin

While rotating 90 degree clockwise (x , y) becomes (y , -x)

Point A' : (-1, -2) ---> (-2, 1)

Point B': (0, 1) -----> (1,0)

Point C' : (0, -1) -----> (-1 ,0)