look at yo periodic table to find the atomic mass
it says that there is 22.98g of sodium (Na) in 1 mol of sodium
1 mol is 6.022 * 10^23 atoms
one way we can do this is ratio and proportion
![(grams_1)/(mols_1)=(grams_2)/(mols_2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lxlenf5jf2ehx0z9eriayg1sme033rb5ph.png)
we are solving for
![grams_2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/h52ofzq4ln8m9102pulw6nt77mmtgaiqm3.png)
multiply both sides by
![mols_2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pp749ux9wc5nrzskw4anqjl2baknbfemgm.png)
![((grams_1)(mols_2))/(mols_1)=grams_2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/r5rrieyoy3pp3ggb4dg40usg1euijq7kml.png)
let's say
=22.98g and
and
![mols_2=1.3*10^(21)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/q32d889wlb88z9r751j1lv0gusfen3vi75.png)
therefor
![((22.98g)(1.3&10^(21)mol))/(6.022*10^(23)mol)=grams_2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fma62k6qr2aqhsicft7lny39daugbygy2w.png)
![0.0496081g=grams_2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/a9jpy9fowu4l5l58vjzp4gxfzvfar1oko8.png)
so it weighs about
![5.0*10^(-2)g](https://img.qammunity.org/2019/formulas/mathematics/middle-school/z3vaa2lsd1r7fp40xl2p3oi47p16nrcy35.png)