If you try to do this in your calculator, it will explode simply because of how large the number is. This question can be solved - BY HAND - with factors and exponent rules.
The factors of 10 are 2 and 5 and 1 and 10. We use 2 and 5 in this problem as we can write

So,
![10^(999) * 5^(-998) * 2^{-997]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/c5ht1s8w171wbcy4u8i5g2gjyhhdd4w4ro.png)



For the next problem, if we take apart the first part and write it as
, we have all our exponents adding to zero, and any nonzero power to a zero exponent is 1.
Thus, the two computations are 20 and 1.