Take a look at f(x) = -x + 1. Its slope is negative and its y-intercept is +1.
Right away, we can eliminate the 3rd and 4th graphs, because they show positive slopes for x≤1.
Take another look: f(x) = -x + 1. When x = 0, y = 1. Thus, the y-intercept is (0,1).
The first graph shows this intercept correctly; the second does not. So the correct answe is "the first graph."