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Find The X Intercepts of the quadratic equation f(x)= (3/5)((x^2)+6x-5)

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The x intercepts are the zeros, the roots of the the equation f(x)=0.



(3/5) (x^2 + 6x - 5) = 0



x^2 + 6x - 5 = 0


That one doesn't factor but it is amenable to the Shakespeare Quadratic Formula (2b or -2b).
x^2-2bx+c has zeros
x=b \pm √(b^2-c)



x = -3 \pm √(14)


Those are the two x intercepts,


Answer:
\quad x = -3 -√(14) \textrm{ and } x = -3 + √(14)



User Sandesh Sharma
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