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A solid gold cube with edge of 2" is melted down and recast as a cone with a 3" radius base. Find the height of the cone.

User Swaechter
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1 Answer

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Volume of cube = s^3


Volume of cone = (1/3)Ah


Cube:


V = s^3 = (2 in.)^3 = 8 in.^3


Cone:


V = (1/3) *pi * (3 in.)^2 * h = 8 in.^3


pi * 9h = 24 in.


h = 24/(9pi) in.


h = 8/(3pi) in.


h is approximately equal to 0.849 in.


Answer: The height is (8/3)pi inches which is approximately 0.849 inches

User OBu
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