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Find the 6th term of the geometric sequence, given the first term and common ratio a1= 5 and r=3/2

User Roudan
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1 Answer

4 votes

Answer



37.96875



Step-by-step explanation

In geometric sequence we use the formula below to find the nth of a sequence.


Tn = ar⁽ⁿ⁻¹⁾

Where a ⇒ first term

n ⇒ the term we are looking for

T₆ = 5 × (3/2)⁶⁻¹

= 5 × (3/2)⁵

= 5 × 243/32

= 1215/32

= 37 31/32

= 37.96875

User Nikos Tsagkas
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