Question

What are the solutions to the quadratic equation -2x^2 + 6x + 3 = 0?

Answer 1

For this, we will be using the quadratic formula, which is
`x=(-b+/-√(b^2-4ac))/(2a)`, with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this:
`x=(-6+/-√(6^2-4*(-2)*3))/(2*(-2))`

Firstly, solve the multiplications and the exponents:
`x=(-6+/-√(36+24))/(-4)`

Next, do the addition:
`x=(-6+/-√(60))/(-4)`

Next, your equation will be split into two:
`x=(-6+√(60))/(-4),(-6-√(60))/(-4)` . Solve them separately, and your answer will be
`x=-0.436,3.436`