In a 30 -- 60 -- 90 triangle, the pattern for the legs is always this:
Shorter leg: 1
Longer leg:

Hypotenuse: 2
(Try checking that with the Pythagorean Theorem).
With this 1 - tex] \sqrt{3} [/tex] - 2 pattern, we go to the problem. Since the longer leg is tex] 16 \sqrt{3} [/tex], the shorter leg is going to be 16. Think of the tex] \sqrt{3} [/tex] as being tex] 1 \sqrt{3} [/tex], and we multiplied it by (or scaled it up) by a factor of 16.
So the triangle's short leg is 16 in this problem.