Question

23 grams of sodium reacts with 244 cm3 of water that is initially at 293 K. It produces an enthalpy change of 71 kJ. What is the final temperature of the water? The specific heat capacity of water is 4.18 J/K

g.

Answer 1

362.6 K

Step-by-step explanation:

Answer for Quiz- Enthalpy via Founder's Education

Answer 2

Given mass of Na is 23 g

Volume of water =
`244 cm^(3)`

Mass of water =
`244 cm^(3) * ( 1 g)/(cm^(3)) = 244 g`

Total solution mass = 23 g + 244 g = 267 g

Specific heat capacity of water = 4.18 J/K.g

Equation relating mass, heat, specific heat capacity and temperature change is:

`q = m C`ΔT

`71 kJ * (1000 J)/(1 kJ) = 267 g ( 4.18 (J)/(k.g) )(Tfinal - 293 K)`

`71,000 J = (1116.06 (J)/(K))(Tfinal - 293 K)`

Tfinal = 356.6 K

Therefore, the final temperature of water will be 356.6 K