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Write the equation of the line that passes through (-4,3) and is perpendicular to the line y=7/5x-3/5 A) 5x+7y=1 B) 7x+5y=-13 C) 7x+5y=-1 D) 3x+5y=7
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Write the equation of the line that passes through (-4,3) and is perpendicular to the line y=7/5x-3/5

A) 5x+7y=1
B) 7x+5y=-13
C) 7x+5y=-1
D) 3x+5y=7

User Diogo Rosa
by
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1 Answer

4 votes
Since it is perpendicular the slope will be -5/7
y=mx+b plug in the point given
3=(-5/7)(-4)+b
3=20/7+b
b=1/7
y=(-5/7)x+(1/7)
(y=(-5/7)x+(1/7))*7 get rid of fraction
7y=-5x+1. add over the -5x
5x+7y=1
The answer is A.
User Kenttam
by
7.2k points
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