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ΔABC is reflected across line L to form Δ ALBLCL, and `barAbar(A_L)` intersects line L at point

d. Which equation is not necessarily true?

User Asmeurer
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1 Answer

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Reflection of triangle ABC is nothing but flipping of triangle over a line L.

The triangle ABC is the pre image and the triangle A'B'C' is the image after reflection. D can be any point on the line L.

From the attached figure we can clearly see that

AD =
A_(L)D

BD =
B_(L)D

CD =
C_(L)D

The corresponding angles are equal.

So we can say that A_LD =
B_(L)D is not necessarily true.

ΔABC is reflected across line L to form Δ ALBLCL, and `barAbar(A_L)` intersects line-example-1
ΔABC is reflected across line L to form Δ ALBLCL, and `barAbar(A_L)` intersects line-example-2
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