Question

Help me on this question please!

An inequality is shown below:

−np − 6 ≤ 3(c − 5)

Which of the following solves for n?

n ≥ − the quantity 3 times c minus 21 all over p
n ≥ − the quantity 3 times c minus 9 all over p
n ≤ − the quantity 3 times c minus 21 all over p
n ≤ − the quantity 3 times c minus 9 all over p

Answer 1

it is the 2 sentence

Answer 2

The correct option is B)
`n\geq (-3c+9)/(p)`.

Explanation:

Consider the provided inequality:

`-np - 6 \leq 3(c - 5)`

Now distribute 3 inside the parentheses.

`-np - 6\leq 3c - 15`

Add 6 on both the side of the inequality:

`-np-6+6\leq 3c-15+6`

`-np\leq 3c-9`

Now, multiply both the sides by a negative sign and reverse the sign of inequality.

`np\geq -3c+9`

Divide both the sides of the inequality by p.

`n\geq (-3c+9)/(p)`

Now consider the provided options.

By observing the provided option it can be concluded that the correct option is B)
`n\geq (-3c+9)/(p)`.