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Find the equation of the line through the point (-2,-2) that is perpendicular to the line y=2x-1

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A line perpendicular to y = 2x - 1 must have the slope -1/2 (negative reciprocal of 2).


Thus, the eq'n of the new line is y+2 = (-1/2)(x+2).

User Pezholio
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